If n = 2^k then log(n) is irrational. But Sum{1/k} is ever rational . Then Sum{1/k} - Log(n) is ever irrational.. Ludovicus
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CSI of Charles University
Euler-Masqueroni contant
If n = 2^k then log(n) is irrational. But Sum{1/k} is ever rational . Then Sum{1/k} - Log(n) is ever irrational.. Ludovicus